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November 23, 2014

November 23, 2014

Posted by **David** on Monday, February 23, 2009 at 11:54am.

- Math -
**Reiny**, Monday, February 23, 2009 at 2:27pm(x-2)/(x-1) = 1 - 1/(x-1)

so

integral[(x-2)/(x-1)] = integral[1 - 1/(x-1)

= x - ln(x-1) + C

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