Post a New Question

posted by David Monday, February 23, 2009 at 11:54am.

antiderivative of (x-2)/(x-1)

(x-2)/(x-1) = 1 - 1/(x-1) so integral[(x-2)/(x-1)] = integral[1 - 1/(x-1) = x - ln(x-1) + C

More Related Questions