Posted by Bob on Monday, February 23, 2009 at 9:39am.
Yes, your procedure is correct. I obtained 147.014 for CaCl2.2H2O and 100.087 for CaCO3 but I'm using a calculator on the internet and that may not agree with the numbers on your periodic table. They should agree if both contain the most up to date information. Using my numbr I obtained 2.0219 g for the theoretical yield, which rounds to 2.02. Here is the site I use for molar mass calculations if you wish to compare their numbers versus your numbers. http://environmentalchemistry.com/yogi/reference/molar.html
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