Posted by Li on Sunday, February 22, 2009 at 8:55pm.
Well, if you found the answer to the first and second question, you should be able to figure that out via the kinematics equations esp if you got the height question
that's the problem, I can't....
Use conservation of energy. The kinetic energy when it hits the tree will be
(1/2) M V2^2 = (1/2) M V1^2 + M g H
where h is the 1.2 m distance that it falls vertically and V1 is the initial velocity of 18 m/s. The M's cancel. Solve for V2
V2^2 = V1^2 + 2 g H
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