You did not restate the second problem bu by the structure of your equations, I can tell it must be
.25x + .10y = .19(20) for the second equation.
Hint: multiply that equation by 100 to get rid of those nasty decimals, then from the first y=20-x
sub that back into the second and its easy from there on.
I got x=20
let me know if you did not get that.
Here's what I did
-10(.25x + .10y = .19(20))
I multiplied it by -10 so I could easily do the Elimination method.
That gets me:
-2.5x + -1y = -38
Then, I added the equations together to get:
-1.5x = -18
I divided both sides by -1.5 and that got me x = 12.
Did I go wrong somewhere? The thing is, then that makes y = 8, and when I substituted that into the second equation, it was correct. Were you wrong?
<3 Valeria <3
you are right,
when I looked back at my solution on the paper in front of me, I did have x =12
(I have no idea why I typed x = 20, perhaps I was looking at your previous question)
BTW, I had suggested multiplying by 100, since the longest decimal string has 2 places of decimal,
You multiplied by 10, which still left you with decimals to work with.
Of course if you are comfortable working with decimals, (a calculator doesn't care), then you could just as well work with the original equations
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