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November 26, 2014

November 26, 2014

Posted by **Jordana** on Sunday, February 22, 2009 at 2:20am.

A. The ball falls into the green slots 4 or more times.

Probability =

B. The ball does not fall into any green slots.

Probability =

C. The ball falls into black slots 11 or more times.

Probability =

D. The ball falls into red slots 12 or fewer times.

Probability =

- statistics help needed -
**drwls**, Sunday, February 22, 2009 at 2:31amWe will be glad to critique your thinking.

- statistics help needed -
**Jordana**, Sunday, February 22, 2009 at 2:41amI don't know if I use the poisson function in excel. I just don't know how to start the problem.

I can find the probability of hitting a green slot in one time but not multiple times.

- statistics help needed -
**drwls**, Sunday, February 22, 2009 at 3:36amPoisson statistics is not the only way to do these problems, but it can provide an approximate result for some.

For B, the probability is that of no-green 24 times in a row. (36/38)^24 = (18/19)^24 = 0.273 That was easy

For A, add the probabilities of getting green 4,5,6...24 etc times in 24 attempts. The sum will rapidly converge.

Probability of 4 green:

(1/19)^4*(18/19)^20*C(24,4)= 0.02765

Probability of 5:

(1/19)^5*(18/19)^19*C(24,5) = 0.00614

Probability of 6:

(1/19)^6*(18/19)^18*C(24,6) = 0.00108

Probability of 7:

(1/19)^7*(18/19)^17*C(24,7) = 0.00015

Probability of 4 or more: 0.0350

If a Poisson distribution is used, for n = 24 spins with p = 1/19 probability of green each time, a = np = 1.26316

P(4) = a^4*e^-1.236/4! = 0.03082

You still have to add up P(5), P(6) etc.

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