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January 27, 2015

January 27, 2015

Posted by **Alex** on Saturday, February 21, 2009 at 6:39pm.

lim(x-->0) (1-cosx)/2x^2

I multiplied the numerator and denominator by (1+cosx) to get

lim(x->0) (1-cos^2x)/2x^2(1+cosx)

= lim(x->0)sin^2x/2x^2(1+cosx)

the lim(x->0) (sinx/x)^2 would =1

I then substituted the remaining portion with 0 and got 1/4

Is this answer right??

- Calculus..more help! -
**bobpursley**, Saturday, February 21, 2009 at 8:04pmOne of the ways to check these is to look a graph of it. Yes, it is right.

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