Post a New Question

Calculus..more help!

posted by .

I have a question relating to limits that I solved
lim(x-->0) (1-cosx)/2x^2
I multiplied the numerator and denominator by (1+cosx) to get
lim(x->0) (1-cos^2x)/2x^2(1+cosx)
= lim(x->0)sin^2x/2x^2(1+cosx)
the lim(x->0) (sinx/x)^2 would =1
I then substituted the remaining portion with 0 and got 1/4
Is this answer right??

  • Calculus..more help! -

    One of the ways to check these is to look a graph of it. Yes, it is right.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question