Posted by **kj** on Saturday, February 21, 2009 at 1:00am.

Two ropes are attached to a skater as sketched in the figure below and exert forces on her as shown. Find the magnitude and direction of the total force exerted by the ropes on the skater if θ1 = 32.0° and θ2 = 53.0°.

what is the magnitude and direction (horizontal) ?

- physics -
**drwls**, Saturday, February 21, 2009 at 1:14am
You have not provided enough information for us to help you. The magnitudes of the two forces, F1 and F2, are needed. The total force component along the axis from which the angles are measured will be

Fx = F1 cos 32 + F2 cos 53.

Along the perpendicular axis the net force component is

Fy = F1 sin 32 + F2 sin 53.

The magnitude of the resultant force is

F = sqrt(Fx^2 + Fy^2)

and the direction is tan^1 Fy/Fx

## Answer This Question

## Related Questions

- Physics - Three people pull horizontally on ropes attached to a post, as shown ...
- PHYSICS - The three ropes in the figure are tied to a small, very light ring. ...
- math - Forces are applied to two ropes which are attached to the bumper of a ...
- physics - Two fi gure skaters are moving east together during a performance. ...
- physics - a 650 lb box is hanging by means of two ropes attached to a ceiling as...
- Physics - Suppose your car was mired deeply in the mud and you wanted to use the...
- science - Three horizontal ropes pull on a large stone stuck in the ground, ...
- Physics - The helicopter view in the figure below shows two people pulling on a ...
- physics - A skater with 60 kg mass pushes a skater of 80 kg with a 68 N force. ...
- physics - A skater with 60 kg mass pushes a skater of 80 kg with a 68 N force. ...

More Related Questions