Math
posted by Dan .
Use the functions f(x)=1/8x3 and
g(x)=x^3 to find the indicated value or function.
(g^1 X f^1)(3)

f^1)(3) is the value of x that you get when f(x) = 3. That value is 0.
g^1(0) is the value of x that you get when g(x) = 0. That is also zero.
So (g^1*f^1)(3) = 0
In functional form,
f^1(x) = 8(x+3)
g^1(x) = x^(1/3)
(g^1*f^1)(x) = [8(x+3)]^1/3
2(x+3)^1/3