Homework Help: i lied. very quick calc problem.

Posted by jane on Friday, February 20, 2009 at 1:00am.

f(x) = abs(sin(x)), -pi less than or equal to x less than or equal to pi
g(x) = x^2

let H(x) = g(f(x))
i got that H(x) would equal sin^2(x).

THIS IS WHERE I AM STUCK!
find the domain of H. do i still need to account for "-pi less than or equal to x less than or equal to pi" or is it all real numbers?

i lied. very quick calc problem. - drwls, Friday, February 20, 2009 at 2:18am
Since they put that restriction on the domain of f(x), the same restriction should apply to g(f(x)). Ignore my previous comment about the domain being all real numbers in this case.

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