Wednesday

April 1, 2015

April 1, 2015

Posted by **joel** on Thursday, February 19, 2009 at 7:18pm.

- calculus -
**drwls**, Thursday, February 19, 2009 at 7:29pmLet u = 1-2x^3

du = =6 x^2 dx

Your integral is INTEGRAL u^1/2*(-du/6)

= -(1/6)*u^(3/2)/(3/2)

= -(1/9)(1-2x^3)^(3/2)

Check my math

- calculus -
**joel**, Thursday, February 19, 2009 at 7:33pmthanks

**Answer this Question**

**Related Questions**

calculus i need help please - evaluate: integration of x^2 (square root of (1-2x...

Calculus - Find the exact area of the region enclosed by the square root of (x...

college pre-calculus - simplify: square root (4/3)-square root (3/4) A. 2-...

calculus - evaluate the ∫from square root of 2 to 2 1/x^3square root of x^...

calculus - how do you solve the integral of 1/[(square root of x)(lnx)] from 2 ...

Calculus - square root of (12), square root of (12 + square root of (12)), ...

Math simplifying mixed radicals - Please help me simplify these following mixed ...

Algebra - Rationalize each expression by building perfect nth root factors for ...

calculus - Evaluate lim as x-> 0 square root (x+1) - square root (2x+1) / ...

calculus - Evaluate lim as x-> 0 square root (x+1) - square root (2x+1) / ...