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posted by joel on Thursday, February 19, 2009 at 7:18pm.

evaluate: integration of x^2 (square root of (1-2x^3))dx

Let u = 1-2x^3 du = =6 x^2 dx Your integral is INTEGRAL u^1/2*(-du/6) = -(1/6)*u^(3/2)/(3/2) = -(1/9)(1-2x^3)^(3/2) Check my math

thanks

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