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December 22, 2014

December 22, 2014

Posted by **joel** on Thursday, February 19, 2009 at 7:18pm.

- calculus -
**drwls**, Thursday, February 19, 2009 at 7:29pmLet u = 1-2x^3

du = =6 x^2 dx

Your integral is INTEGRAL u^1/2*(-du/6)

= -(1/6)*u^(3/2)/(3/2)

= -(1/9)(1-2x^3)^(3/2)

Check my math

- calculus -
**joel**, Thursday, February 19, 2009 at 7:33pmthanks

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