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Posted by on Thursday, February 19, 2009 at 7:18pm.

evaluate: integration of x^2 (square root of (1-2x^3))dx

  • calculus - , Thursday, February 19, 2009 at 7:29pm

    Let u = 1-2x^3
    du = =6 x^2 dx
    Your integral is INTEGRAL u^1/2*(-du/6)
    = -(1/6)*u^(3/2)/(3/2)
    = -(1/9)(1-2x^3)^(3/2)

    Check my math

  • calculus - , Thursday, February 19, 2009 at 7:33pm

    thanks

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