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January 29, 2015

January 29, 2015

Posted by **Tessa** on Thursday, February 19, 2009 at 4:12pm.

x-y=0

y=x²

The reason I don't understand the question is the second equation with the x². How do I graph that? I'm not sure if I ever graphed with an exponent, and if I did, it was a long time ago.

Thanks!

- algebra -
**Damon**, Thursday, February 19, 2009 at 4:36pmUnless you have a typo, this is a very easy problem

Your first equation says that y = x

your second equation means that y = x^2

This is only true at (0,0) and (1,1))

Now:

y = x is a straight line in quadrants 1 and three at 45 degrees to the x axis

y = x^2 is a parabola, facing up (holds water) with vertex at (0,0)

other points at

(-3,9),(-2,4), (-1,1) (0,0),(1,1),(2,4),(3,9)

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