Posted by **TP** on Thursday, February 19, 2009 at 1:21am.

I just had a test, and one question I tried heaps of times and I still couldn't answer. It was "Prove secèsinè + cosecè cosè = 2cosecè "

Can someone please tell me if proving this is possible at all? (But don't tell me how to solve it)

- Maths - Trig -
**Damon**, Thursday, February 19, 2009 at 4:30am
sin x/cos x + cos x/sin x =

(sin^2 x + cos^2 x)/(sin x cos x )=

1/(sin x cos x)

I do not see how that comes out to 2 cosec x

- Maths - Trig -
**Reiny**, Thursday, February 19, 2009 at 9:30am
Usually my first step in proving any trig identity is taking an arbitrary angle to see if it makes it true, say 45 degrees.

Picking up from Damon's first line, your equation is

tanx + cotx = 2/sinx

for x = 45 degrees

LS = 1+1 = 2

RS = 2/.707 which is not LS

so the equation is not an identity.

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