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Posted by on Wednesday, February 18, 2009 at 9:55pm.

This was an SAT question of the day, but I can't figure out how to come up with the right answer, I think you use Pythagoras Theorum but I'm not sure. Can anyone help with the process here?

A 25-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on concrete 7 feet from the base of the building. If the top of the ladder slips down 4 feet, then the bottom of the ladder will slide out ___ ft.

  • Geometry/ SAT Math - , Wednesday, February 18, 2009 at 10:04pm

    Nevermind I figured it out!

  • Geometry/ SAT Math - , Wednesday, February 18, 2009 at 10:05pm

    Before the slipping occurs, the top of the ladder's distance above the floor is
    sqrt(25^2 - 7^2) = 24 feet
    If the top slips 4 feet, it then is 20 feet from the floor.
    Now use the Pythagorean theorem again to get the distance of the base from the vertical wall.
    sqrt (25^2 - 20^2) = __?__

  • Geometry/ SAT Math - , Sunday, May 2, 2010 at 12:13am

    15

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