Posted by **anonymous** on Wednesday, February 18, 2009 at 9:55pm.

This was an SAT question of the day, but I can't figure out how to come up with the right answer, I think you use Pythagoras Theorum but I'm not sure. Can anyone help with the process here?

A 25-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on concrete 7 feet from the base of the building. If the top of the ladder slips down 4 feet, then the bottom of the ladder will slide out ___ ft.

- Geometry/ SAT Math -
**anonymous**, Wednesday, February 18, 2009 at 10:04pm
Nevermind I figured it out!

- Geometry/ SAT Math -
**drwls**, Wednesday, February 18, 2009 at 10:05pm
Before the slipping occurs, the top of the ladder's distance above the floor is

sqrt(25^2 - 7^2) = 24 feet

If the top slips 4 feet, it then is 20 feet from the floor.

Now use the Pythagorean theorem again to get the distance of the base from the vertical wall.

sqrt (25^2 - 20^2) = __?__

- Geometry/ SAT Math -
**allen jang**, Sunday, May 2, 2010 at 12:13am
15

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