Posted by anonymous on Wednesday, February 18, 2009 at 9:55pm.
This was an SAT question of the day, but I can't figure out how to come up with the right answer, I think you use Pythagoras Theorum but I'm not sure. Can anyone help with the process here?
A 25foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on concrete 7 feet from the base of the building. If the top of the ladder slips down 4 feet, then the bottom of the ladder will slide out ___ ft.

Geometry/ SAT Math  anonymous, Wednesday, February 18, 2009 at 10:04pm
Nevermind I figured it out!

Geometry/ SAT Math  drwls, Wednesday, February 18, 2009 at 10:05pm
Before the slipping occurs, the top of the ladder's distance above the floor is
sqrt(25^2  7^2) = 24 feet
If the top slips 4 feet, it then is 20 feet from the floor.
Now use the Pythagorean theorem again to get the distance of the base from the vertical wall.
sqrt (25^2  20^2) = __?__

Geometry/ SAT Math  allen jang, Sunday, May 2, 2010 at 12:13am
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