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April 1, 2015

April 1, 2015

Posted by **Lisa** on Wednesday, February 18, 2009 at 9:05pm.

four minus three fourths b to the 5th power c to the third power divided by negative four sixths b to the second power and c to the negative 2 power

- algebra -
**Reiny**, Wednesday, February 18, 2009 at 9:26pmthe way you typed it , and the way you stated it,

I would multiply top and bottom by 12 to get rid of the fractions.

(48 - 9b^{5}c^{3})/(-8b^{2}c^{-3}) or perhaps

(48c^{3}- 9b^{5}c^{6})/-8b^{2}

other than that I see little else that I would do

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