4-3/4b^5c^3 / -4/6b^2c^-3 =
four minus three fourths b to the 5th power c to the third power divided by negative four sixths b to the second power and c to the negative 2 power
algebra - Reiny, Wednesday, February 18, 2009 at 9:26pm
the way you typed it , and the way you stated it,
I would multiply top and bottom by 12 to get rid of the fractions.
(48 - 9b5c3)/(-8b2c-3) or perhaps
(48c3 - 9b5c6)/-8b2
other than that I see little else that I would do