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August 22, 2014

August 22, 2014

Posted by **Jevette** on Wednesday, February 18, 2009 at 2:39am.

1. 3(x-5)-2(3x+1)+14=5(1-x)+3(x-12)-x

2. (x-1)^2 + (2-x)(x+2)+3=(x+2)^2-x^2+3x-5

3. (x+3)^2-(x-1)(1+x)+1=x^2+x+7-(x-2)^2

4. (1-x)^2-(2+x)(2-x)+4x=11(x^2-x)-(2-3x)^2+12

5. (2x-3)^2-(x+1)(1-x)+x=(3x-1)^2+(1-2x)(2x+1)-9

6. (2x-1)^2-(x+3)^2+x=(x+1)(1-x)+4(x^2-6x-1)

7. (3x-2)^2-(4+x)(x-4)+3x=(1-2x)^2+4(x^2-2x+3)+19

Thank you~

- Grade 10 Math -
**drwls**, Wednesday, February 18, 2009 at 6:15amI do not know if you are supposed to combine terms or solve for x.

The first problem can be rewritten

3x - 15 -6x -2 + 14

= 5 - 5x + 3x -36 - x

Now combine terms

-3x -3 = -3x -31

This is an impossibility since it leads to -3 = -31.

The original statement cannot be correct.

- Grade 10 Math -
**jigar**, Monday, February 28, 2011 at 6:26pm3-3

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