Posted by Gregg on Wednesday, February 18, 2009 at 12:15am.
Ohhh ,i'm on this chapter right now. Okay, is there a value for x? if not, make an x and y table chart, i normally start with zero which i highly recomend you doing.
okay once you decide on what you are going to set x as, fill it in like this:
Example- C(0)= 16(0)+130
C(0)= 0 +130
C(0)= 130
You try it now.
if you have any questions, i'm right here waiting to answer them.
5,250=16x+130
16x=5,250-130
16x=5,120
x=5,120/16
x=320
7,810=16x+130
16x=7,810-130
16x=7,680
x=7,680/16
x=480
This is what I came up with is this correct?
I got the same thing. I hope it's right
what did you set x as?
oh, i get it , you're trying to do the linear equation type of way, he's talking about linear functions, you know... f(x)=mx+b
So is {x| 320 < x <480 correct?
Where did this question come from?
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