Posted by Chris on Wednesday, February 18, 2009 at 12:02am.
if the year 2000 matches t = 0, then
the year 1945 matches t = -55
so we have 1350 = 2500e^(-55k)
.54 = e^(-55k)
using natural logs,
-55k = ln(.54)
k = .011203384
so the equation is p = 2500e^(.011203384t)
in 2010 , t = 10
so
p = 2500E(.011203384*10)
= 2796
You are a god.
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