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March 6, 2015

March 6, 2015

Posted by **Jeff** on Tuesday, February 17, 2009 at 10:49pm.

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:00pmUhh im not sure if this is right but i think you should first put it in slope intercept form.

then make an X and Y chart to find solutions.

y=4x-7

(0,-7)

(1, -3)

(2, 1)

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:04pmWould (2,1) (3,5) and (4,9) work as well? Thanks!

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:05pmyea i got (2,1) in my first post. Yeah, they should all work.

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:06pmEven though you switched it to the y = 4x - 7? Is this all the same or is the -7 and 7 the constants changed? Thanks

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:08pmno, when i put in slope intercept form i got -7

the original equation was

4x-y=7

subtract 4x to both sides

-y=-4x+7

you cant have a -y so move the negative over, this will change the sign of everything

y=4x-7

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:09pmif you had 4x+y=7

then the slope intercept form of that would be

y=-4x+7

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:11pmSo which is the correct method? Switching the original, or just using variables as i did to make the equation true

4x-y = 7

4(2) - 1 = 7 (2,1)

4(3) - 5 = 7 (3,5)

4(4) - 9 = 7 (4,9)

Which method is correct? Or does it not matter because the equation has infinate solutions? Thanks!

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:15pmBoth method is fine.

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:16pmAre you a math teacher? Just wondering?

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:16pmno im not. but im in alg 2

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:17pmThat makes sense..High School?

- Algebra -
**Chopsticks**, Tuesday, February 17, 2009 at 11:19pmyeah high school.

- Algebra -
**Jeff**, Tuesday, February 17, 2009 at 11:23pmOk! Have a good night and thanks for the help!

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