Algebra
posted by Jeff on .
4x  y = 7 I need ordered pairs for this linear equation, I was wondering of some possible solutions. Thanks!

Uhh im not sure if this is right but i think you should first put it in slope intercept form.
then make an X and Y chart to find solutions.
y=4x7
(0,7)
(1, 3)
(2, 1) 
Would (2,1) (3,5) and (4,9) work as well? Thanks!

yea i got (2,1) in my first post. Yeah, they should all work.

Even though you switched it to the y = 4x  7? Is this all the same or is the 7 and 7 the constants changed? Thanks

no, when i put in slope intercept form i got 7
the original equation was
4xy=7
subtract 4x to both sides
y=4x+7
you cant have a y so move the negative over, this will change the sign of everything
y=4x7 
if you had 4x+y=7
then the slope intercept form of that would be
y=4x+7 
So which is the correct method? Switching the original, or just using variables as i did to make the equation true
4xy = 7
4(2)  1 = 7 (2,1)
4(3)  5 = 7 (3,5)
4(4)  9 = 7 (4,9)
Which method is correct? Or does it not matter because the equation has infinate solutions? Thanks! 
Both method is fine.

Are you a math teacher? Just wondering?

no im not. but im in alg 2

That makes sense..High School?

yeah high school.

Ok! Have a good night and thanks for the help!