Posted by **Darcie** on Monday, February 16, 2009 at 11:41pm.

my daughter is doing homework using greatest common factor, greatest common divisor, and prime factorization. She has this problem: Computers in the research room of the history museum are 30 wide, 30 inches apart and at either end of a row 30 inches from the wall. How many computers can fit across a room that is 25 feet wide?

I can do the problem in my head but I don't know how to explain it to her or to tell her how to show her work. What is the teacher looking for on how to solve this problem? I've tried to read the chapter over and over again and it doesn't make sense to me whatsoever.

- math -
**Damon**, Tuesday, February 17, 2009 at 10:59am
30 inches = 2.5 ft

25 ft-2.5 ft = 22.5 ft left after space is left for 2.5 ft space at the far wall

Each computer/space unit takes 60 inches or 5 feet.

so

22.5/5 = 4.5 computer/space units

So only four will fit if you leave 30 inches from the wall at each end. If you only have the 30 inch space at one wall, you can get five in.

- math -
**Anonymous**, Wednesday, April 24, 2013 at 3:22pm
4

## Answer this Question

## Related Questions

- Math Grade 5 - my daughter is doing homework using greatest common factor, ...
- Greatest Common factors - I dont know these answers. Can you help me? Greatest ...
- Math - Which is the expression that can be factored using the greatest common ...
- MATH 117 - What is the greatest common factor (HINT: It may help for you to show...
- Math - If a is the greatest common factor of 72 and 48, and if b is the greatest...
- pseudo code and flow charts - how can write a pseudo code and a flow charts to ...
- coomon factors - I don't understand common factors. can someone show me how to ...
- Fib. Number - I noticed someone else is having problems with the same problem ...
- math - 1. What is the greatest common factor of: 2x2x5x7x7 2x5x5x7x7 a. 2x5 b. ...
- Math (Greatest common factor) - Please Help! I dont understand the question ...

More Related Questions