Tuesday

September 30, 2014

September 30, 2014

Posted by **Anonymous** on Monday, February 16, 2009 at 10:13pm.

Basically, theres's a square. The battery voltage(12V) is on the left side. The R1=2 is on the top side of the square and R2=0 ohms is on the right side of the square.

The total current of the series is 6 A and the voltage is 12 A.

I know in series, the current is the same for all resistors so since R2=0 ohms, will the voltage for R2 and Current for R2 be zero while voltage for R1 is 12 V and current for R1 is 6 Amps.

or will current for R2 be 6 Amps as well.

- circuits -
**Damon**, Tuesday, February 17, 2009 at 10:33amEvery electron that goes through R1 has to go through R2.

Therefore the current through R2 is 6 amps just like through R1.

The voltage drop V = i R2 is zero across R2 because its resistance is zero.

**Answer this Question**

**Related Questions**

physics - so i have a circuit (series) where the the emf=12 V and R1=2 ohms and ...

physics - a battery with and emf of 12V and an internal resistance of 0.5 ohms, ...

Physics - Circuits - Theres a circuit wired in series that has 4 resistors. 1) ...

Physics - A battery with voltage drop of 120V is connected in a ciruit ...

physics - Please check my work here: Resistors of 30 ohms and 60 ohms are ...

Physics - A battery with voltage drop of 120V is connected in a ciruit ...

Physics - I'm totally confused and this is due Monday- We're dealing with ...

circuits - If a series RLC circuit has R = 25 ohm, XL = 50 ohms, and XC = 30 ...

Physics - Batteries are not perfect. Instead they have an "internal resistance, ...

science - Calculate the resistance in a circuit in which a 9-volt battery ...