so i have a circuit (series) where the the emf=12 V and R1=2 ohms and R2=0 ohms.

Basically, theres's a square. The battery voltage(12V) is on the left side. The R1=2 is on the top side of the square and R2=0 ohms is on the right side of the square.

The total current of the series is 6 A and the voltage is 12 A.

I know in series, the current is the same for all resistors so since R2=0 ohms, will the voltage for R2 and Current for R2 be zero while voltage for R1 is 12 V and current for R1 is 6 Amps.

or will current for R2 be 6 Amps as well.

Every electron that goes through R1 has to go through R2.

Therefore the current through R2 is 6 amps just like through R1.
The voltage drop V = i R2 is zero across R2 because its resistance is zero.

In a series circuit, the current remains the same through all the components. So, in this case, the current will be 6 Amps throughout the circuit, including both resistors R1 and R2.

However, when we consider the voltage across each component, it depends on the resistance. The voltage across a resistor is given by Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) through it multiplied by the resistance (R). So, for R1 with a resistance of 2 ohms and a current of 6 Amps, the voltage across R1 will be:

V1 = I * R1 = 6 A * 2 Ω = 12 V

Now, for R2, the resistance is given as 0 ohms. According to Ohm's law, if the resistance is zero, the voltage across the resistor will also be zero, regardless of the current. Therefore, the voltage across R2 will indeed be zero, and the current through R2 will also be zero since there is no voltage drop across it.

To summarize:
- The current through the entire circuit will be 6 Amps.
- The voltage across R1 will be 12 Volts and the current through R1 will be 6 Amps.
- The voltage across R2 will be zero, and no current will flow through R2.