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November 20, 2014

November 20, 2014

Posted by **Anonymous** on Monday, February 16, 2009 at 10:13pm.

Basically, theres's a square. The battery voltage(12V) is on the left side. The R1=2 is on the top side of the square and R2=0 ohms is on the right side of the square.

The total current of the series is 6 A and the voltage is 12 A.

I know in series, the current is the same for all resistors so since R2=0 ohms, will the voltage for R2 and Current for R2 be zero while voltage for R1 is 12 V and current for R1 is 6 Amps.

or will current for R2 be 6 Amps as well.

- circuits -
**Damon**, Tuesday, February 17, 2009 at 10:33amEvery electron that goes through R1 has to go through R2.

Therefore the current through R2 is 6 amps just like through R1.

The voltage drop V = i R2 is zero across R2 because its resistance is zero.

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