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Posted by on Monday, February 16, 2009 at 8:27pm.

I'm supposed to factor this:
3z^2-17z+24

I used the quadratic equation, but I'm not sure if that's what I was supposed to use to get the answer. This is how I worked it...

-(-17)+/-sqrt(-17^2-4(3)(24)
---------------------------
2(3)
17+/-sqrt(289-288)
------------------
6
17 sqrt (1) = 17
----------- ----
6 6

is 17/6 correct?

  • math - , Monday, February 16, 2009 at 8:42pm

    the numbers are quite small, so a few trial and error runs would give you

    (x-3)(3x-8)

    your method should have given you
    (17 +/- 1)/6 = 3 or 8/3

    the root of 3 would have given the x-3 factor
    the 8/3 would yield the (3x-8) factor

  • math - , Monday, February 16, 2009 at 8:45pm

    (3z- )(z - )
    (3z- 4 )(z -6 ) no
    (3z- 6)(z -4 )no
    (3z- 8)(z - 3) YES

  • math - , Monday, February 16, 2009 at 9:15pm

    oh :( okay I definitely used the wrong method then. trial and error is a lot less steps than I used. thank you

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