Posted by Megan on Monday, February 16, 2009 at 7:21pm.
Write the balanced equation.
2Al + 6HCl ==> 2AlCl3 + 3H2
Convert 15.0 g Al to moles.
Convert 15.0 g HCl to moles.
15.0 g Al x (1 mole Al/26 g) = 0.555
15.0 g HCl x (1 mole HCl/36.5 g) = 0.410
Convert moles of each to mols of either product (but stay consistent). Let's choose AlCl3.
0.555 moles Al x (2 moles AlCl3/2 moles Al) = 0.555 x 1/1 = 0.555 moles AlCl3.
0.410 moles HCl x (2 moles AlCl3/6 moles HCl) = 0.410 x 2/6 = 0.137 moles AlCl3.
The SMALLER number of moles produced by the HCl means two things: (a) HCl is the limiting reagent, and (b)0.137 moles AlCl3 is the amount of product formed using 15.0 g of each reactant initially.
Now convert moles AlCl3 to grams.
0.137 moles AlCl3 x (133.5 g AlCl3/1 mole AlCl3) = 18.3 g.
All of the problems are worked this way. Just follow this template. And you need to redo this one from the beginning for two reasons. First, I estimated the atomic masses and molar masses and you need to use the exact values to obtain a correct answer. Second, you need the practice and this can be a good practice problem because you know the answers for each step.
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