A heavy bank-vault door is opened by the application of a force of 3.0 10^2N directed perpendicular to the plane of the door at a distance of 0.80 m from the hinges. What is the torque?

300 N * m ?!?!?

300 N * .8 m

Torque (or "moment of force") is force component perpendicular to the direction to the fulcrum(hinge) times distance to the fulcrum

To calculate the torque exerted on the bank-vault door, you can use the formula:

Torque = Force * Distance * sin(θ)

In this case, the force applied is 3.0 * 10^2 N and the distance from the hinges is 0.80 m. Since the force is directed perpendicular to the plane of the door, the angle (θ) between the force and the radius is 90 degrees, which means sin(90) equals 1.

Plugging in the values into the formula:

Torque = 3.0 * 10^2 N * 0.80 m * sin(90)
= 3.0 * 10^2 N * 0.80 m * 1
= 2.4 * 10^2 N * m

Therefore, the torque exerted on the bank-vault door is 2.4 * 10^2 N * m.