Sunday

September 21, 2014

September 21, 2014

Posted by **Anonymous** on Monday, February 16, 2009 at 6:11am.

Thanks!

- Math: Integration -
**drwls**, Monday, February 16, 2009 at 6:44amThese conditions must be satisfied:

6 = a*2^2 + b*2 + c = 4a + 2b + c

16 = 9a + 3b + c

dy/dx @ P = 2a*2 + b = 4a + b = 7

Solve those three equations in 3 unknowns. It does not require integral calculus.

4a + 2b + c = 6

4a + b = 7

Combine these two to get b + c = -1

36a + 12 b + 4c = 64

36a + 18 b + 9c = 54

Combine the last 2 to get

6b + 5c = -10

Now you have two equations in two unknowns. Use substitution to eliminate one of the variables.

6b + 5(-1 -b) = -10

b = -5

4a = 7-b = 12 ; a = 3

5c = -10 -6b = -10 + 30 = 20

c = 4

y = 3x^2 -5x + 4

**Answer this Question**

**Related Questions**

calculus - A curve passes through the point (1,-11) and it's gradient at any ...

Mathamatics - This question concerns the straight line that passes through the ...

Math - This question concerns the straight line that passes through the points...

Maths - a curve ahs parametric equations x=t^2 and y= 1-1/2t for t>0. i)find ...

Math - How can I determine a value of gradient from a graph if the line is ...

Maths - Hi, need a bit of help on this one. A straight line passes through the ...

Calculus - Maths - I got a few questions. Hope ya'll can help out. 1) for F(X...

Maths - Please help, I need to calculate the gradient of a straight line that ...

maths - Find the gradient of the straight line that passes through the points (3...

maths - The curve C with equation y=fx passes through the point (3, 14/2) given ...