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March 24, 2017

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Consider 57.5 mL of a solution of weak acid HA (Ka = 1.00 10-6), which has a pH of 3.800. What volume of water must be added to make the pH = 6.000?

  • Chemistry - ,

    Change pH to (H^+).
    Write Ka expression.
    Plug in (H^+) and (A^-) and solve for (HA).
    Then change pH 6.00 to (H^+). Write Ka expression, plug in (H^+), (A^-) and solve for new (HA). Then calculate how much water must be added to convert concn from 3.80 material to concn you want at 6.00 concn.

  • Chemistry - ,

    how do u calc how much water is needed?

  • Chemistry - ,

    Molarity*liters of 1 soln = molarity*liters of other solution.

  • Chemistry - ,

    for the second set i put Ph=6 and got H+=1e-6 and then HA=1e6

    i think that's wrong.. whats wrong with it?

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