Homework Help: Chemistry

Posted by Brian on Sunday, February 15, 2009 at 11:54pm.

Consider 57.5 mL of a solution of weak acid HA (Ka = 1.00 10-6), which has a pH of 3.800. What volume of water must be added to make the pH = 6.000?

Chemistry - DrBob222, Monday, February 16, 2009 at 12:27am
Change pH to (H^+).
Write Ka expression.
Plug in (H^+) and (A^-) and solve for (HA).
Then change pH 6.00 to (H^+). Write Ka expression, plug in (H^+), (A^-) and solve for new (HA). Then calculate how much water must be added to convert concn from 3.80 material to concn you want at 6.00 concn.
Chemistry - brian., Monday, February 16, 2009 at 11:15am
how do u calc how much water is needed?
Chemistry - DrBob222, Monday, February 16, 2009 at 2:24pm
Molarity*liters of 1 soln = molarity*liters of other solution.
Chemistry - Brian, Monday, February 16, 2009 at 2:49pm
for the second set i put Ph=6 and got H+=1e-6 and then HA=1e6

i think thats wrong.. whats wrong with it?

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