A hollow plastic sphere is held below the surface of a freshwater lake by a cord anchored to the bottom of the lake. The sphere has a volume of 0.600m^3 and the tension in the cord is 840N . What is the mass of the sphere? And Calculate the buoyant force exerted by the water on the sphere.
Tension=bouyant force-mg=volume*densitywater*g-mg
= you do it.
To find the mass of the sphere, we need to use the equation:
density = mass/volume
In this case, we have the volume of the sphere (0.600 m^3), but we don't have the density. However, we can use the density of freshwater to calculate the mass.
The density of freshwater is approximately 1000 kg/m^3.
So, mass = density * volume
mass = 1000 kg/m^3 * 0.600 m^3
mass = 600 kg
Therefore, the mass of the hollow plastic sphere is 600 kg.
Now, let's calculate the buoyant force exerted by the water on the sphere. The buoyant force can be found using the equation:
buoyant force = weight of the fluid displaced
The weight of the fluid displaced is equal to the weight of the volume of water equal to the volume of the sphere.
So, weight of the fluid displaced = density of freshwater * volume
weight of the fluid displaced = 1000 kg/m^3 * 0.600 m^3
weight of the fluid displaced = 600 kg
Therefore, the buoyant force exerted by the water on the sphere is 600 kg.