Posted by jessie on Sunday, February 15, 2009 at 8:31pm.
well yes sort of but the normal force you are talking about is that giving centripetal acceleration
m v^2/R
at the top of the loop, m g the weight is down
However a normal force in the down direction of m v^2/R is required to keep the person moving in the circular loop.
So as long as m v^2/R is greater than m g, the person does not fall out.
so in the end
v^2/R >/= g
is the condition for not falling out of the roller coaster.
Related Questions
Physics - we are doing a really dumb websearch in my Physics class on roller ...
physics - 3.A roller coaster has a vertical loop with radius 27.1 m. With what ...
physics - A roller coaster has a vertical loop with radius 17.9 m. With what ...
physics - Part of a roller-coaster ride involves coasting down an incline and ...
Physics- Elena please help! - Part of a roller-coaster ride involves coasting ...
physics - A certain roller coaster has a circular, vertical loop of radius 10 ...
physics - A certain roller coaster has a circular, vertical loop of radius 10 ...
physics - A certain roller coaster has a circular, vertical loop of radius 10 ...
physics - A roller coaster of mass 1000.0 kg passes point A with a speed of 1.80...
Math - A group of 378 people are standing in line to ride a roller coaster.If ...
For Further Reading