Posted by **BEARHUG** on Sunday, February 15, 2009 at 1:59pm.

1) A Motor Company has purchased steel parts from a supplier for several years and has found that 10% of the parts must be returned because they are defective. An order of 25 parts is received. What are the mean and standard deviation of the defective parts?

A) Mean = 3.5; standard deviation = 2.5

B) Mean = 2.5; standard deviation = 1.5

C) Mean = 1.5; standard deviation = 2.5

D) Mean = 2.5; standard deviation = 3.5

2)Given a binomial random variable with n = 15 and = 0.4, find the following probability using the binomial table. P (6 < x < 10)

A) 0.0338

B) 0.1181

C) 0.0947

D) 0.3564

- Statistics -
**Mathguru**, Monday, February 16, 2009 at 9:41am
For 1).

Your values are the following:

p = .1, q = 1 - p = .9, and n = 25

To find mean and standard deviation:

mean = np = (25)(.1) = ?

standard deviation = √npq = √(25)(.1)(.9)= ?

I'll let you finish the calculations to answer the question.

For 2).

Use the binomial table to determine your answer for the values given.

I hope this will help get you started.

## Answer this Question

## Related Questions

- math - Three out of 200 machine parts were found to be defective. About how many...
- math - Three out of 200 machine parts were found to be defective. About how ...
- Math - Three out of 200 machine parts were found to be defective. About how many...
- Math - Three out of 200 machine parts were found to be defective. About how many...
- stats - Suppose a shipment of 500 machine parts contains 62 defective and 438 ...
- Statistics - I'm stuck on this homework question. If someone can just help get ...
- statistics - Suppose a shipment of 500 machine parts contains 62 defective and ...
- Statistics - Can someone please help me with this example, I do not understand ...
- statistic math - it is known that 5% of all parts manufactured at Plant F are ...
- Statistics - Half of a set of the parts are manufactured by machine A and half ...