Monday

September 15, 2014

September 15, 2014

Posted by **Mai** on Sunday, February 15, 2009 at 2:06am.

The photoelectric work function of a metal is the minimum energy needed to eject an electron by irradiating the metal with light. For calcium, this work function equals 4.34X10^(-19)J. What is the minimum frequency of light required to observe the photoelectric effect in calcium?

- college: Chemistry -
**GK**, Sunday, February 15, 2009 at 8:39pmThis question should have been posted on the PHYSICS board.

- college: Chemistry -
**DrBob222**, Sunday, February 15, 2009 at 8:50pmdelta E = hf

Substitute 4.34 x 10^-19 for delta E, substitute Planck's constant for h and calculate frequency.

- college: Chemistry -
**Anonymous**, Tuesday, September 22, 2009 at 9:36pm1.53e-15

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