Tuesday
September 16, 2014

Homework Help: math

Posted by jona on Saturday, February 14, 2009 at 5:24pm.

I'm trying to solve by completing the square but i always get stuck at the end..
3x^2-6x+2=0
3(x^2-2x)+2=0
3(x^2-2x+1-1)+2=0
3(x-1)^2 -1 =0
3(x-1)^2=1
now what do i do?... the answer is supposed to be x=3+-(square root)of3-> the whole thing over 3

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