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January 30, 2015

January 30, 2015

Posted by **Julia** on Saturday, February 14, 2009 at 5:06pm.

- Algebra -
**Damon**, Saturday, February 14, 2009 at 5:16pmassuming no compunding of interest:

borrow x at .15

borrow (x+800) at .12

then

.15 x + .12 (x+800) = 420

- Algebra -
**Reiny**, Saturday, February 14, 2009 at 5:17pmlet his loan from the bank be $x

let the loan from the credit union be $(x+800)

.15x + .12(x+800) = 420

solve for x, let me know what you got.

- Algebra -
**Julia**, Saturday, February 14, 2009 at 5:21pmThere has to be two equations. I got 1,200 for x...

- Algebra -
**Damon**, Saturday, February 14, 2009 at 5:39pm1200 and 2000 are the correct amounts.

- Algebra -
**Damon**, Saturday, February 14, 2009 at 5:44pmIf you really, really, want to make two equations out of this:

x = amount at .15

y = amount at .12

then

.15 x + .12 y = 420

y = x + 800

then substitute equation 2 into equation 1

.15 x + .12(x+800) = 420

which is where we started.

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