Homework Help: physics

Posted by y912f on Saturday, February 14, 2009 at 2:43pm.

please show me in steps how to solve this

thanks alot!

A bobsled zips down an ice track, starting from rest at the top of a hill with a vertical height of 150m. Disregarding friction, what is the velocity of the bobsled at the bottom of the hill? (g=9.81 m/s^2)

any help is appreciated :)

physics - Damon, Saturday, February 14, 2009 at 3:15pm
loss of potential energy = kinetic energy at bottom
m g h = (1/2) m v^2
9.81 * 150 = (1/2) v^2
solve for v

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