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September 16, 2014

September 16, 2014

Posted by **y912f** on Saturday, February 14, 2009 at 2:43pm.

thanks alot!

A bobsled zips down an ice track, starting from rest at the top of a hill with a vertical height of 150m. Disregarding friction, what is the velocity of the bobsled at the bottom of the hill? (g=9.81 m/s^2)

any help is appreciated :)

- physics -
**Damon**, Saturday, February 14, 2009 at 3:15pmloss of potential energy = kinetic energy at bottom

m g h = (1/2) m v^2

9.81 * 150 = (1/2) v^2

solve for v

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