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posted by on .

please show me in steps how to solve this

thanks alot!

A bobsled zips down an ice track, starting from rest at the top of a hill with a vertical height of 150m. Disregarding friction, what is the velocity of the bobsled at the bottom of the hill? (g=9.81 m/s^2)

any help is appreciated :)

  • physics - ,

    loss of potential energy = kinetic energy at bottom
    m g h = (1/2) m v^2
    9.81 * 150 = (1/2) v^2
    solve for v

  • physics - ,


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