A rock is dropped from a very tall tower. If it takes 4.1 s for the rock to reach the ground, what is the height of the tower?

h=0.5gt^2

assume that the tower is on Earth and thus g=9.8 m s^-2

To determine the height of the tower, we can use the formula for free fall motion, which relates the height (h) in meters to the time (t) in seconds it takes for an object to fall:

h = (1/2) * g * t^2

In this case, we are given the time it takes for the rock to reach the ground (4.1 seconds). Additionally, we know that the acceleration due to gravity (g) is approximately 9.8 m/s^2.

Now, let's substitute the given values into the formula to find the height of the tower:

h = (1/2) * 9.8 * (4.1)^2

Calculating this expression will give us the answer:

h ≈ 84.454 meters

Therefore, the height of the tower is approximately 84.454 meters.