Sunday

November 23, 2014

November 23, 2014

Posted by **Shannon** on Friday, February 13, 2009 at 2:05am.

I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))

- Calculus -
**drwls**, Friday, February 13, 2009 at 2:16amHow on earth did you get that mess? Just add the separate integrals of 8x and -x^2.

The answer is

4x^2 - (x^3)/3

To verify, differentiate it and see if you get 8x-x^2 back again.

- Calculus -
**Shannon**, Friday, February 13, 2009 at 2:46amSorry, it is evaluate the indefinite integral: sqrt(8x-x^2)

- Calculus -
**Anonymous**, Saturday, August 30, 2014 at 7:05pm2y*y'=x/sqrt(x^2-16)

**Answer this Question**

**Related Questions**

Math Help please!! - Could someone show me how to solve these problems step by ...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...

Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...

Math - How do you find a square root of a number that's not a perfect square? I'...

Inequality - When I solve the inquality 2x^2 - 6 < 0, I get x < + or - ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

MATH - I need to simply this equation, but I got stuck. h/(4-sqrt(16+h)) = y ...