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August 31, 2015

Homework Help: Calculus

Posted by Shannon on Friday, February 13, 2009 at 2:05am.

Evaluate the indefinite integral: 8x-x^2.

I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))

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