Posted by **Shannon** on Friday, February 13, 2009 at 2:05am.

Evaluate the indefinite integral: 8x-x^2.

I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))

- Calculus -
**drwls**, Friday, February 13, 2009 at 2:16am
How on earth did you get that mess? Just add the separate integrals of 8x and -x^2.

The answer is

4x^2 - (x^3)/3

To verify, differentiate it and see if you get 8x-x^2 back again.

- Calculus -
**Shannon**, Friday, February 13, 2009 at 2:46am
Sorry, it is evaluate the indefinite integral: sqrt(8x-x^2)

- Calculus -
**Anonymous**, Saturday, August 30, 2014 at 7:05pm
2y*y'=x/sqrt(x^2-16)

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