Posted by **Shannon** on Friday, February 13, 2009 at 2:05am.

Evaluate the indefinite integral: 8x-x^2.

I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))

- Calculus -
**drwls**, Friday, February 13, 2009 at 2:16am
How on earth did you get that mess? Just add the separate integrals of 8x and -x^2.

The answer is

4x^2 - (x^3)/3

To verify, differentiate it and see if you get 8x-x^2 back again.

- Calculus -
**Shannon**, Friday, February 13, 2009 at 2:46am
Sorry, it is evaluate the indefinite integral: sqrt(8x-x^2)

- Calculus -
**Anonymous**, Saturday, August 30, 2014 at 7:05pm
2y*y'=x/sqrt(x^2-16)

## Answer This Question

## Related Questions

- Math Help please!! - Could someone show me how to solve these problems step by ...
- Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...
- Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...
- Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...
- Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...
- Math - How do you find a square root of a number that's not a perfect square? I'...
- Inequality - When I solve the inquality 2x^2 - 6 < 0, I get x < + or - ...
- math calculus please help! - l = lim as x approaches 0 of x/(the square root of...
- math,algebra,help - Directions are simplify by combining like terms. x radiacal ...
- Calculus check - Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f ...

More Related Questions