Monday

December 22, 2014

December 22, 2014

Posted by **Hannah** on Friday, February 13, 2009 at 1:49am.

- Calculus -
**drwls**, Friday, February 13, 2009 at 1:56amLet w = 2x^3

6x^2 dx = dw

The integral becomes the integral of

(1/6)w cos w, which can be solved using integration by parts to give

(1/6)[cos w + w sin w]

= (1/6)[cos(2x^3) + 2x^2 sin(2x^3)]

- Calculus -
**Reiny**, Friday, February 13, 2009 at 8:03amWouldn't it simply be

(1/6)sin(2x^3) + c ?

- Calculus -
**drwls**, Friday, February 13, 2009 at 8:39amThe derivative of Reiny's answer is

(1/6)cos(2x^3)*6x^2 = x^2 cos(2x^3), so I must have made a mistake somewhere.

**Answer this Question**

**Related Questions**

calculus - 1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (...

Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...

Calc 1 - integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2...

Integral calculus - Please can anyone help with the following problems - thanks...

Calculus - 6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b...

calculus 2 - Justify, with a written explanation or a mathematical reasoning ...

integrate - integrate du/3u and integrate x/x^2 dx it might be simple...i just ...

PLZ integrate - integrate cos^3x dx tnk U

Calculus AB - Please help me integrate this equation using partial fractions: ...

calculus help please - dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into ...