A water solution which contains magnesium chloride as the only solute measured 232 parts per million chloride on an analytical instrument using a specific ion electrode as the sensor unit. When converted to moles per liter what value would you get for the chloride ion concentration?
232 ppm = 232 g Cl^-/10^6 g solution =
232 x 10^-6 g Cl^-/g solution. Since the solution is so dilute, the density of the solution will be essentially 1.00 g/mL; therefore, this is equivalent to 232 x 10^-6 g Cl^-/mL or for a liter it is
232 x 10^-6 x (1000 mL/1L) = 232 x 10^-3 g Cl^-/L. Convert that to moles/L to obtain molarity. Check my work.
To convert the concentration of chloride from parts per million (PPM) to moles per liter (M), you need to follow a few steps:
Step 1: Convert PPM to milligrams per liter (mg/L)
To convert PPM to mg/L, you need to know the conversion factor, which is 1 PPM = 1 mg/L for most solutions. Therefore, the chloride concentration in mg/L will also be 232 mg/L.
Step 2: Convert milligrams to moles
To convert the chloride concentration from mg/L to moles per liter (M), you need to divide the mass in milligrams by the molar mass of chloride. The molar mass of chloride is 35.45 g/mol.
1 mg/L = 1 x 10^(-6) grams per liter (g/L)
Chloride concentration in g/L = 232 x 10^(-6) g/L = 0.232 g/L
0.232 g/L x (1 mol / 35.45 g) = 0.00654 mol/L
Therefore, the chloride ion concentration in moles per liter would be approximately 0.00654 mol/L.