Posted by isha on Thursday, February 12, 2009 at 9:09pm.
the sum of the roots of the original is 3/2
the product of the roots is -2
so a+b = 3/2
ab = -2
sum of new roots = 1/a + 1/b = (a+b)/(ab)
= (3/2) / -2 = -3/4
product of new roots - (1/a)(1/b) = 1/(ab) = -1/2
so the new equation is
x^2 + (3/4)x - 1/2 = 0 or
4x^2 + 3x - 2 = 0
based on the theorem that for
ax^2 + bx + c = 0
the sum of the roots is -b/a and
the product of the roots is c/a
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