Posted by Katy on Thursday, February 12, 2009 at 6:07pm.
I assume the acceptable values are in the triangle.
so for the bottom line:
y=mx+b the two points are 2,1 and 11,3
y=2/9 x+ b ( m= (y1-y2)/(x1-x2)
then to solve for b
3=2/9 *11 + b
b=3-22/9=5/9
so the solution area here, is all above the line, or y>2x/9 + 5/9
Now consider the left line
y=mx+ b (m= (9-1)/7-2)=8/5
y=8x/5+b solve for b...
9=8*7/5+b
b=9-56/5=-11/5
and the solution set is below the line,or
y<8x/5-11/5
Then to the last line the same way, the solution set will be below that line.
Those three equations are your system of inequalities.
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