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March 30, 2015

March 30, 2015

Posted by **luke** on Thursday, February 12, 2009 at 12:49am.

- physics -
**drwls**, Thursday, February 12, 2009 at 6:34am3 full turns is 6 pi radians.

Call the angular speed at the end of 3 turns w(3).

The three turns require time T, where

w(3) = 10.8 + 22.4*T

[w(3)+ 10.8]*T/2 = 6 pi

T = 12 pi/[w(3)+ 10.8]

= [w(3)-10.8]/22.4

w(3)^2 - (10.8)^2 = 22.4*(12 pi)

Solve for w(3)

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