posted by Andrew on .
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot was in view for a total of 0.37 s, and the top-to-bottom height of the window is 2.20 m. How high above the window top did the flowerpot go?
S= ut +(1/2)at^2
S= (0)(0.215) + (0.5)(9.8)(0.215)^2
That's what I did and the site tells me I'm wrong. Please help.
Duplicate post--already answered.