dy/dx = (y-1)^2 cosπx

There's a horizontal line with equation y=c that satisfies this differential equation. Find the value of c.

if it is a horizontal line, then dy/dx=0

0=(c-1)^2 cosPIx
so c has to be 1

To find the value of c that satisfies the given differential equation, we need to substitute y=c into the equation and solve for c.

Let's substitute y=c into the equation dy/dx = (y-1)^2 cos(πx):

dy/dx = (c-1)^2 cos(πx)

Since the derivative dy/dx represents the slope of the function, for a horizontal line, the slope is always zero. Therefore, we have:

0 = (c-1)^2 cos(πx)

Since the cosine function varies from -1 to 1, the only way for the right side of the equation to be zero is if (c-1)^2 = 0.

Solving for c, we have:

(c-1)^2 = 0

Taking the square root of both sides, we get:

c-1 = 0

Adding 1 to both sides, we have:

c = 1

Therefore, the value of c that satisfies the differential equation is 1.

To find the value of c that satisfies the differential equation dy/dx = (y-1)^2 * cos(πx), we can substitute y = c into the equation and determine what condition it needs to satisfy.

Substituting y = c, the differential equation becomes dc/dx = (c-1)^2 * cos(πx).

We want to find the value of c for which this equation is satisfied for all x. This means that the expression on the right-hand side of the equation, (c-1)^2 * cos(πx), should be equal to zero for all x.

To determine when the expression (c-1)^2 * cos(πx) is equal to zero, we look for the cases where either (c-1)^2 is equal to zero or cos(πx) is equal to zero.

For (c-1)^2 to be equal to zero, c must be equal to 1. However, this does not guarantee that (c-1)^2 * cos(πx) will be equal to zero for all x.

For cos(πx) to be equal to zero, x must be any integer. Combining this with c = 1, we find that the horizontal line with equation y = c will satisfy the differential equation dy/dx = (y-1)^2 * cos(πx) if and only if c = 1 and x is an integer.

Therefore, the value of c that satisfies the differential equation is c = 1.