posted by anonymous .
For the reaction shown, compute the theoretical yield of product (in grams) for each of the following initial amounts of reactants.
2Al(s) +3 Cl2(g) ---> 2 AlCl3(s)
A. 2.5gAl , 2.5g Cl2
B. 7.7 g Al , 25.2 g Cl2
C. 0.240 g Al , 1.10 g Cl2
1. Convert 2.5 g Al to moles.
2. Convert 2.5 g Cl2 to moles.
3a. Convert moles Al to moles AlCl3.
3b. Convert moles Cl2 to moles AlCl3.
3c. Compare 3a and 3b; the smaller number of moles of AlCl3 will tell you which material (Al or Cl2) is the limiting reagent.
4. Convert moles from 3c to grams.
The others are done the same way.