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December 19, 2014

December 19, 2014

Posted by **vanessa** on Wednesday, February 11, 2009 at 8:12pm.

log3x-log5=1

- algebra 2 honors -
**Reiny**, Wednesday, February 11, 2009 at 10:32pmlog3x-log5=1

log (3x/5) = 1

then 3x/5 = 10^1

3x = 50

x = 50/3

check:

log(3(50/3)) - log5

= log50-log5

= 1.69897 - .69897

= 1

- algebra 2 honors -
**kimberli**, Saturday, April 10, 2010 at 11:11amhow do u solve

(6/4x^2)+ (2/5x)

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