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posted by vanessa on Wednesday, February 11, 2009 at 8:12pm.

how do you solve problems like : log3x-log5=1

log3x-log5=1 log (3x/5) = 1 then 3x/5 = 10^1 3x = 50 x = 50/3 check: log(3(50/3)) - log5 = log50-log5 = 1.69897 - .69897 = 1

how do u solve (6/4x^2)+ (2/5x)

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