Ammonia has the formula NH3. Household ammonia is a dilute aqueous solution of NH3 . Aqueous ammonia is a base that can neutralize acids.
If 18.4mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?
Moles HCl=MolesAmmonia
Molarity*Volume=
.8*.0184= ?? Moles
Molar concentrationAmmonia = above moles/.005
Are you saying that the molar concentration is .005
Nevermind I figured it out with your help. The answer was 2.94. Thank you so much!
Do you think you know how to figure out this one:
Sorry about that
The chemical 5-amino-2,3-dihydro-1,4-phthalazinedione, better known as luminol, is used by forensic scientists in analyzing crime scenes for the presence of washed-away blood. Luminol is so sensitive that it can detect blood that has been diluted 10,000 times. A basic solution of luminol is often sprayed onto surfaces that are suspected of containing minute amounts of blood.
Luminol has a molecular weight of 177g/mol
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 14.0 of luminol into a total volume of 75.0 mL of H2O.
1. What is the molarity of the stock solution of luminol?
ANSWER:molarity of luminol solution =1.05 M
2.Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 . The diluted solution is then placed in a spray bottle for application on the desired surfaces.
How many moles of luminol are present in 2.00 L of the diluted spray?
ANSWER: moles of luminol =0.120
3.What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
Answer: needs to be in mL and i cant figure it out. Can someone please help
I've responded to your multiple post multiple times.
just times your liter answer by 10^3 =)
To solve this problem, we can use the concept of stoichiometry and the balanced equation for the reaction between HCl and NH3 to determine the molar concentration of the ammonia solution.
The balanced equation for the reaction is:
NH3 + HCl -> NH4Cl
From the equation, we can see that 1 mole of NH3 reacts with 1 mole of HCl to form 1 mole of NH4Cl.
Given the volume and molar concentration of the HCl solution, we can calculate the number of moles of HCl:
moles of HCl = volume of HCl solution (in L) × molar concentration of HCl
Converting the volume of HCl solution to liters:
volume of HCl solution = 18.4 mL = 18.4 × 10^(-3) L
Substituting the values:
moles of HCl = (18.4 × 10^(-3) L) × (0.800 mol/L)
Next, we need to find the number of moles of NH3 that reacted with the HCl. According to the balanced equation, the molar ratio between NH3 and HCl is 1:1.
Therefore, the number of moles of NH3 reacted = moles of HCl
Now, we can calculate the molar concentration of the NH3 solution:
molar concentration of NH3 = moles of NH3 reacted / volume of NH3 solution (in L)
Given the volume of the NH3 solution:
volume of NH3 solution = 5.00 mL = 5.00 × 10^(-3) L
Substituting the values:
molar concentration of NH3 = moles of NH3 reacted / (5.00 × 10^(-3) L)
Finally, substitute the value of moles of NH3 reacted (which is equal to the moles of HCl calculated earlier) and solve for the molar concentration of NH3.