The chemical 5-amino-2,3-dihydro-1,4-phthalazinedione, better known as luminol, is used by forensic scientists in analyzing crime scenes for the presence of washed-away blood. Luminol is so sensitive that it can detect blood that has been diluted 10,000 times. A basic solution of luminol is often sprayed onto surfaces that are suspected of containing minute amounts of blood.

Luminol has a molecular weight of 177g/mol

The forensic technician at a crime scene has just prepared a luminol stock solution by adding 14.0 of luminol into a total volume of 75.0 of .

1. What is the molarity of the stock solution of luminol?
ANSWER:molarity of luminol solution =1.05
2.Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 . The diluted solution is then placed in a spray bottle for application on the desired surfaces.

How many moles of luminol are present in 2.00 L of the diluted spray?
ANSWER: moles of luminol =0.120

3.What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?

Answer: needs to be in mL and i cant figure it out. Can someone please help

answered below.

To find the volume of the stock solution that contains the same number of moles as the diluted solution, we can use the equation:

moles = molarity × volume

First, let's find the number of moles of luminol in the diluted spray solution.

moles of luminol = 0.120

Now, we need to find the molarity of the stock solution. We know that the stock solution was prepared by adding 14.0 g of luminol into a total volume of 75.0 mL.

Let's convert the mass of luminol into moles:

moles of luminol = mass / molar mass
moles of luminol = 14.0 g / 177 g/mol
moles of luminol = 0.079 moles

Next, let's calculate the molarity of the stock solution:

molarity of stock solution = moles / volume
molarity of stock solution = 0.079 moles / 75.0 mL
molarity of stock solution = 0.00105 M

Now we can use the equation moles = molarity × volume to find the volume of the stock solution containing the same number of moles as the diluted solution.

volume of stock solution = moles / molarity
volume of stock solution = 0.120 moles / 0.00105 M
volume of stock solution = 114.286 mL

Therefore, the volume of the stock solution that contains the same number of moles as the diluted solution is 114.286 mL.