Post a New Question


posted by on .

Two spherical objects are separated by a distance of 2.41 x 10-3 m. The objects are initially electrically neutral and are very small compared to the distance between them. Each object acquires the same negative charge due to the addition of electrons. As a result, each object experiences an electrostatic force that has a magnitude of 4.18 x 10-21 N. How many electrons did it take to produce the charge on one of the objects?

Can you help at all? Please give me an idea where to start. Thank you.

  • physics - ,

    F = Q^2 / (4 pi eps d^2)

    find Q

    then the number electrons is

    N = Q /e

    where e is the electron's charge (look it up)

  • physics - ,

    The distance between them is
    d = 2.41 x 10-3 m

    The charge on each sphere is Q

    The force of each sphere on the other is
    F = k Q^2/d^2 = 4.18 x 10-21 N
    Look up the Coulomb's Law constant k and solve that equation for Q.

    The number of electrons is
    N = Q/e
    where e is the electron charge.

  • physics - ,

    Ok. I did that and I found that Q= 1.64 x 10 ^ -18.

    I then divided that by 1.6 x 10 ^ -19.

    The answer I got was 10.23.

    I am being told that is the wrong answer. Could you please double check that for me?

    Thank you!!

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question