Posted by **Anonymous** on Wednesday, February 11, 2009 at 4:40pm.

Integrate:

f (x)/(2x + 1) dx

let f represent integrate sign

let u = x, du = dx => dx = du

= f (u)/(2u + 1) du

= f u (2u + 1)^(-1) du

= (1/2)u^2 (ln|2u + 1|) + c

= (1/2)x^2 (ln|2x + 1|) + c

...what did I do wrong? The correct answer is

(1/2)x - (1/4)ln|2x + 1| + c

## Answer this Question

## Related Questions

- Integral calculus - Please can anyone help with the following problems - thanks...
- Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...
- Integration of exponents with absolute values - I cannot for the life of me ...
- calculus - 1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (...
- integrate - how do i integrate 2u du /u-2+2u^2 so i used subsitution rule? or ...
- Calc 1 - integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2...
- integrate - integrate du/3u and integrate x/x^2 dx it might be simple...i just ...
- calculus-integration - integrate -2/xln^4(x)...plz help me..give me an idea on ...
- Calculus - 6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b...
- calculus 2 - Justify, with a written explanation or a mathematical reasoning ...

More Related Questions