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October 24, 2014

October 24, 2014

Posted by **Mario** on Wednesday, February 11, 2009 at 5:58am.

- Algebra -
**Dr Russ**, Wednesday, February 11, 2009 at 6:25amAfter 1 half life it will have 0.5 (or 1/2^1) remaining

After 2 half lifes it will have 0.25 (or 1/2^2)remaining

After 3 half lifes it will have 0.125 (or 1/2^3) remaining

After n half lifes it will have 1/2^n remaining

There is 0.086 remaining so

0.086 = 1/2^n

or 2^n=1/0.086

solve for n to give you the number of half lives

and n x 2 x 10^6 y = age of meteorite.

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