Ca(ClO3)2 + KCl --> CaCl2 + 3O2 + KCl
Mass of test tube = 7.918g
Mass of KCl/Ca(ClO3)2 mixture + tube = 19.164g
Mass of KCl/CaCl2 residue + tube = 18.635g
What is the weight % of Ca from the Ca(ClO3)2 impurity in the original mixture?
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I keep getting an answer of 5.89% and 69.9% but im not sure if that's correct