Posted by Jake on Wednesday, February 11, 2009 at 2:17am.
Calculate the mass of the solid you must measure out to prepare 100 mL of 0.025 M CuSO4.
Note that this salt is a hydrate, so its formula is CuSO4⋅5H2O. You must include the waters of hydration when calculating the formula weights.
Would the following setup yield the correct answer?
(100 mL CuSO4⋅5H2O) x (1 L CuSO4⋅5H2O / 1000 mL CuSO4⋅5H2O) x (0.025 mol CuSO4⋅5H2O / 1 L CuSO4⋅5H2O) x (249.7 g CuSO4⋅5H2O / 1 mol CuSO4⋅5H2O)
= 0.624 g CuSO4⋅5H2O
Any feedback is appreciated. Thanks!

chemistry  Dr Russ, Wednesday, February 11, 2009 at 3:56am
CuSO4.5H2O
RMM=249.68
For 1000 ml of 1M need 249.68g
For 100 ml of 1 M need 24.968 g
For 100 ml of 0.025 M need 24.968 x 0.025 = 0.0624 g
Yes, agreed.

chemistry  Anonymous, Thursday, February 26, 2015 at 10:57am
How many grams of S are needed to produce 10g of CuS?
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