Post a New Question

chemistry

posted by on .

Calculate the mass of the solid you must measure out to prepare 100 mL of 0.025 M CuSO4.

Note that this salt is a hydrate, so its formula is CuSO4⋅5H2O. You must include the waters of hydration when calculating the formula weights.

Would the following set-up yield the correct answer?

(100 mL CuSO4⋅5H2O) x (1 L CuSO4⋅5H2O / 1000 mL CuSO4⋅5H2O) x (0.025 mol CuSO4⋅5H2O / 1 L CuSO4⋅5H2O) x (249.7 g CuSO4⋅5H2O / 1 mol CuSO4⋅5H2O)

= 0.624 g CuSO4⋅5H2O

Any feedback is appreciated. Thanks!

  • chemistry - ,

    CuSO4.5H2O

    RMM=249.68

    For 1000 ml of 1M need 249.68g

    For 100 ml of 1 M need 24.968 g

    For 100 ml of 0.025 M need 24.968 x 0.025 = 0.0624 g

    Yes, agreed.

  • chemistry - ,

    How many grams of S are needed to produce 10g of CuS?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question